Oracle 1z1-829 Real 2024 Braindumps Mock Exam Dumps
1z1-829 Exam Questions | Real 1z1-829 Practice Dumps
Oracle 1Z0-829 exam is a valuable certification that can help Java developers to validate their skills and enhance their career opportunities. Java developers who pass 1z1-829 exam can be considered experts in their field and can work in various roles such as Java developer, software engineer, and architect, among others. Moreover, the certification can also boost their confidence and provide them with the necessary skills to work on large-scale Java applications.
NEW QUESTION # 13
Given:
What is the result?
- A. 1001
100
1000 - B. 101
101
1000 - C. 1001
1001
1000 - D. 100
100
1000
Answer: A
Explanation:
The code fragment is using the bitwise operators & (AND), | (OR), and ^ (XOR) to perform operations on the binary representations of the integer values. The & operator returns a 1 in each bit position where both operands have a 1, the | operator returns a 1 in each bit position where either operand has a 1, and the ^ operator returns a 1 in each bit position where only one operand has a 1. The binary representations of the integer values are as follows:
1000 = 1111101000
100 = 1100100
101 = 1100101
The code fragment performs the following operations:
x = x ^ y; // x becomes 1111010101, which is 1001 in decimal
y = x ^ y; // y becomes 1100100, which is 100 in decimal
x = x ^ y; // x becomes 1100101, which is 101 in decimal
The code fragment then prints out the values of x, y, and z, which are 1001, 100, and 1000 respectively. Therefore, option D is correct.
NEW QUESTION # 14
Given the code fragment:
abstract sealed interface SInt permits Story, Art { default String getTitle() { return "Book Title" ; }
}
Which set of class definitions compiles?
- A. Public interface story extends sInd {}
Public interface Art extends SInt {} - B. Interace story extends STnt {}
Interface Art extends SInt {} - C. Non-sealed interface story extends SInt {}
Non-sealed interaface Art extends Sint {} - D. Non-sealed interface story extends SInt {}
Class Art implements Sint {} - E. Sealed interface Storty extends sInt {}
Non-sealed class Art implements Sint {}
Answer: E
Explanation:
The answer is C because the code fragment given is an abstract sealed interface SInt that permits Story and Art. The correct answer is option C, which is a sealed interface Story that extends SInt and a non-sealed class Art that implements SInt. This is because a sealed interface can only be extended by the classes or interfaces that it permits, and a non-sealed class can implement a sealed interface.
Option A is incorrect because interface is misspelled as interace, and Story and Art should be capitalized as they are the names of the permitted classes or interfaces.
Option B is incorrect because public is misspelled as public, and sInd should be SInt as it is the name of the sealed interface.
Option D is incorrect because a non-sealed interface cannot extend a sealed interface, as it would violate the restriction of permitted subtypes.
Option E is incorrect because both Story and Art cannot be non-sealed interfaces, as they would also violate the restriction of permitted subtypes.
Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Sealed Classes and Interfaces in Java 15 | Baeldung
Sealed Class in Java - Javatpoint
NEW QUESTION # 15
Given the content of the in. tart file:
23456789
and the code fragment:
What is the content of the out .txt file?
- A. 012345678901234
- B. 01234567
- C. 012345678
- D. 0123456789234567
- E. 01234567801234
- F. 0123456789
Answer: F
Explanation:
Explanation
The answer is D because the code fragment reads the content of the in.txt file and writes it to the out.txt file.
The content of the in.txt file is "23456789". The code fragment uses a char array buffer of size 8 to read the content of the in.txt file. The while loop reads the content of the in.txt file and writes it to the out.txt file until the end of the file is reached. Therefore, the content of the out.txt file will be "0123456789".
NEW QUESTION # 16
Given:
Which two should the module-info file include for it to represent the service provider interface?
- A. Provides.com.transport.vehicle.cars.Car with com.transport.vehicle.cars. impt, CatImpI;
- B. Exports com.transport.vehicle;
- C. exports com.transport.vehicle.cars.Car;
- D. Exports com.transport.vehicle.cars;
- E. Requires cm.transport.vehicle,cars:
- F. Requires cm.transport.vehicle,cars:
- G. Provides.com.transport.vehicle.cars.Car impl,CarImp1 to com.transport.vehicle.cars. Cars
Answer: A,C
Explanation:
The answer is B and E because the module-info file should include a provides directive and an exports directive to represent the service provider interface. The provides directive declares that the module provides an implementation of a service interface, which is com.transport.vehicle.cars.Car in this case. The with clause specifies the fully qualified name of the service provider class, which is com.transport.vehicle.cars.impl.CarImpl in this case. The exports directive declares that the module exports a package, which is com.transport.vehicle.cars in this case, to make it available to other modules. The package contains the service interface that other modules can use.
Option A is incorrect because requires is not the correct keyword to declare a service provider interface. Requires declares that the module depends on another module, which is not the case here.
Option C is incorrect because it has a typo in the module name. It should be com.transport.vehicle.cars, not cm.transport.vehicle.cars.
Option D is incorrect because it has a typo in the keyword provides. It should be provides, not Provides. It also has a typo in the service interface name. It should be com.transport.vehicle.cars.Car, not com.transport.vehicle.cars.Car impl. It also has an unnecessary to clause, which is used to limit the accessibility of an exported package to specific modules.
Option F is incorrect because it exports the wrong package. It should export com.transport.vehicle.cars, not com.transport.vehicle.cars.impl. The impl package contains the service provider class, which should not be exposed to other modules.
Option G is incorrect because it exports the wrong package. It should export com.transport.vehicle.cars, not com.transport.vehicle. The vehicle package does not contain the service interface or the service provider class. Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Java Modules - Service Interface Module - GeeksforGeeks
Java Service Provider Interface | Baeldung
NEW QUESTION # 17
Given the code fragments:
Which action prints Wagon : 200?
- A. At line n3, replace readObject (0 with readLine().
- B. At line n2, in the main method signature, add throws IOException, ClassCastException.
- C. At Line n3, replace Car with LuxurayCar.
- D. At Line n1, implement the java.io.AutoCloseable interface
- E. At line n1, implement the java.io, Serializable interface.
- F. At line n2, in the main method signature, add throws IoException, ClassNotFoundException.
Answer: F
Explanation:
The code fragment is trying to read an object from a file using the ObjectInputStream class. This class throws an IOException and a ClassNotFoundException. To handle these exceptions, the main method signature should declare that it throws these exceptions. Otherwise, the code will not compile. If the main method throws these exceptions, the code will print Wagon : 200, which is the result of calling the toString method of the LuxuryCar object that was written to the file. Reference: ObjectInputStream (Java SE 17 & JDK 17) - Oracle, ObjectOutputStream (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 18
Given:
Which statement is true while the program prints GC?
- A. Both the objects previously referenced by t1 are eligible for garbage collection.
- B. Only one of the objects previously referenced by t1 is eligible for garbage collection.
- C. None of the objects are eligible for garbage collection.
- D. Only the object referenced by t2 is eligible for garbage collection.
Answer: A
NEW QUESTION # 19
Given the code fragments:
Which action prints Wagon : 200?
- A. At line n3, replace readObject (0 with readLine().
- B. At line n2, in the main method signature, add throws IOException, ClassCastException.
- C. At Line n3, replace Car with LuxurayCar.
- D. At Line n1, implement the java.io.AutoCloseable interface
- E. At line n1, implement the java.io, Serializable interface.
- F. At line n2, in the main method signature, add throws IoException, ClassNotFoundException.
Answer: F
Explanation:
Explanation
The code fragment is trying to read an object from a file using the ObjectInputStream class. This class throws an IOException and a ClassNotFoundException. To handle these exceptions, the main method signature should declare that it throws these exceptions. Otherwise, the code will not compile. If the main method throws these exceptions, the code will print Wagon : 200, which is the result of calling the toString method of the LuxuryCar object that was written to the file. References: ObjectInputStream (Java SE 17 & JDK 17) - Oracle, ObjectOutputStream (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 20
Given the code fragment:
What is the result?
- A. Cat
Dog - B. Cat
null - C. A NullPointerException is thrown
Cat
Cat - D. Dog
Dog
Answer: B
Explanation:
Explanation
The answer is E because the code fragment creates a new Pet object with the name "Dog" and assigns it to the variable p. Then, it assigns p to p1. Next, it changes the name of p1 to "Cat". Then, it assigns p1 to p. Finally, it sets p to null and prints the name of p and p1. The output will be "Cat" and "null" because p is set to null and p1 still points to the Pet object with the name "Cat".
NEW QUESTION # 21
Given:
What is the result?
- A. Software Game Chess 0
- B. Software Game Chess 2
- C. Software Game Software Game chess 0
- D. Software Game read error
- E. Software Game Software Game Chese 2
- F. Software game write error
Answer: E
Explanation:
Explanation
The answer is B because the code uses the writeObject and readObject methods of the ObjectOutputStream and ObjectInputStream classes to serialize and deserialize the Game object. These methods use the default serialization mechanism, which writes and reads the state of the object's fields, including the inherited ones. Therefore, the title field of the Software class is also serialized and deserialized along with the players field of the Game class. The toString method of the Game class calls the toString method of the Software class using super.toString(), which returns the value of the title field.
Hence, when the deserialized object is printed, it shows "Software Game Software Game Chess 2".
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Serialization and Deserialization in Java with Example
NEW QUESTION # 22
Given the code fragment:
What is the result?
- A. $SIM6D
- B. PT5SPTIMP6D
- C. 5000$60M6D
- D. PT5000PT60MP6D
Answer: D
Explanation:
The code fragment is creating a Duration object with a value of 5000 milliseconds, then printing it. Then, it is creating another Duration object with a value of 60 seconds, then printing it. Finally, it is creating a Period object with a value of 6 days, then printing it. The output will be "PT5000PT60MP6D". Reference: https://docs.oracle.com/javase/8/docs/api/java/time/Duration.html, https://docs.oracle.com/javase/8/docs/api/java/time/Period.html
NEW QUESTION # 23
Given:
What is the result?
- A. 0 CLOUDY
- B. Compilation fails
- C. 0 Snowy
- D. 1 Snowy
- E. 1 RAINY
Answer: C
Explanation:
The code is defining an enum class called Forecast with three values: SUNNY, CLOUDY, and RAINY. The toString() method is overridden to always return "SNOWY". In the main method, the ordinal value of SUNNY is printed, which is 0, followed by the value of CLOUDY converted to uppercase, which is "CLOUDY". However, since the toString() method of Forecast returns "SNOWY" regardless of the actual value, the output will be "0 SNOWY". Reference: Enum (Java SE 17 & JDK 17), Enum.EnumDesc (Java SE 17 & JDK 17)
NEW QUESTION # 24
Given:
What is the result?
- A. Software Game Chess 0
- B. Software Game Chess 2
- C. Software Game Software Game chess 0
- D. Software Game read error
- E. Software Game Software Game Chese 2
- F. Software game write error
Answer: E
Explanation:
The answer is B because the code uses the writeObject and readObject methods of the ObjectOutputStream and ObjectInputStream classes to serialize and deserialize the Game object. These methods use the default serialization mechanism, which writes and reads the state of the object's fields, including the inherited ones. Therefore, the title field of the Software class is also serialized and deserialized along with the players field of the Game class. The toString method of the Game class calls the toString method of the Software class using super.toString(), which returns the value of the title field. Hence, when the deserialized object is printed, it shows "Software Game Software Game Chess 2". Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Serialization and Deserialization in Java with Example
NEW QUESTION # 25
Given:
Which statement is true?
- A. The program throws ClassCastException
- B. The program fails to compile.
- C. The program throws StockException.
- D. The program throws outofStockException.
Answer: B
Explanation:
The answer is B because the code fragment contains a syntax error that prevents it from compiling. The code fragment tries to catch a StockException in line 10, but the catch block does not have a parameter of type StockException. The catch block should have a parameter of type StockException, such as:
catch (StockException e) { // handle the exception }
This is required by the Java syntax for the catch clause, which must have a parameter that is a subclass of Throwable. Without a parameter, the catch block is invalid and causes a compilation error.
Option A is incorrect because the program does not throw a StockException, as it does not compile.
Option C is incorrect because the program does not throw an OutofStockException, as it does not compile.
Option D is incorrect because the program does not throw a ClassCastException, as it does not compile. Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
The try-with-resources Statement (The Java™ Tutorials > Essential Classes > Exceptions) The catch Blocks (The Java™ Tutorials > Essential Classes > Exceptions)
NEW QUESTION # 26
Given:
and the code fragment:
- A. 300.00
CellPhone,ToyCar,Motor,Fan - B. 100.00 CellPhone,ToyCar
- C. 100.00
CellPhone,ToyCar,Motor,Fan - D. 300.00
CellPhone.ToyCar
Answer: A
Explanation:
The code fragment is using the Stream API to perform a reduction operation on a list of ElectricProduct objects. The reduction operation consists of three parts: an identity value, an accumulator function, and a combiner function. The identity value is the initial value of the result, which is 0.0 in this case. The accumulator function is a BiFunction that takes two arguments: the current result and the current element of the stream, and returns a new result. In this case, the accumulator function is (a,b) -> a + b.getPrice (), which means that it adds the price of each element to the current result. The combiner function is a BinaryOperator that takes two partial results and combines them into one. In this case, the combiner function is (a,b) -> a + b, which means that it adds the two partial results together.
The code fragment then applies a filter operation on the stream, which returns a new stream that contains only the elements that match the given predicate. The predicate is p -> p.getPrice () > 10, which means that it selects only the elements that have a price greater than 10. The code fragment then applies a map operation on the filtered stream, which returns a new stream that contains the results of applying the given function to each element. The function is p -> p.getName (), which means that it returns the name of each element.
The code fragment then calls the collect method on the mapped stream, which performs a mutable reduction operation on the elements of the stream using a Collector. The Collector is Collectors.joining (","), which means that it concatenates the elements of the stream into a single String, separated by commas.
The code fragment then prints out the result of the reduction operation and the result of the collect operation, separated by a new line. The result of the reduction operation is 300.00, which is the sum of the prices of all ElectricProduct objects that have a price greater than 10. The result of the collect operation is CellPhone,ToyCar,Motor,Fan, which is the concatenation of the names of all ElectricProduct objects that have a price greater than 10.
Therefore, the output of the code fragment is:
300.00 CellPhone,ToyCar,Motor,Fan
NEW QUESTION # 27
Given:
What is the result?
- A. D D D
- B. B A D
- C. D A D
- D. B A C
Answer: B
Explanation:
Explanation
The answer is C because the code demonstrates the concept of method overloading and type conversion in Java. Method overloading allows different methods to have the same name but different parameters. Type conversion allows values of one data type to be assigned to another data type, either automatically or explicitly. In the code, the class Test has four methods named sum, each with different parameter types: int, float, and double. The main method creates an instance of Test and calls the sum method with different arguments. The compiler will choose the most specific method that matches the arguments, based on the following rules:
If there is an exact match between the argument types and the parameter types, that method is chosen.
If there is no exact match, but there is a method with compatible parameter types, that method is chosen.
Compatible types are those that can be converted from one to another automatically, such as int to long or float to double.
If there is more than one method with compatible parameter types, the most specific method is chosen.
The most specific method is the one whose parameter types are closest to the argument types in terms of size or precision.
In the code, the following method calls are made:
test.sum(10, 10.5) -> This matches the sum(int a, float b) method exactly, so it is chosen.
The result is 20.5, which is converted to int and printed as 20 (B).
test.sum(10) -> This does not match any method exactly, but it matches the sum(double a) method with compatible types, as int can be converted to double automatically. The result is 10.0, which is printed as 10
(A). test.sum(10.5, 10) -> This does not match any method exactly, but it matches two methods with compatible types: sum(float a, float b) and sum(double a, double b). The latter is more specific, as double is closer to the argument types than float. The result is 20.5, which is printed as 20 (D).
Therefore, the output is B A D. References
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Method Overloading in Java
Type conversion in Java with Examples
Java Method Overloading with automatic type conversions
NEW QUESTION # 28
Given the code fragments:
Which is true?
- A. The program prints an exception
- B. The program prints t1 : 1: t2 : 1: t1 : t2 : 2 : in random order.
- C. The program prints t1 : 1: t2 : 1: t1 : 1 : t2 : 1 : indefinitely
- D. The program prints t1 : 1 : t2: 1 : t1 : 2 : t2: 2:
Answer: D
Explanation:
Explanation
The code creates two threads, t1 and t2, and starts them. The threads will print their names and the value of the Atomic Integer object, x, which is initially set to 1. The threads will then increment the value of x and print their names and the new value of x. Since the threads are started at the same time, the output will be in random order. However, the final output will always be t1 : 1 : t2: 1 : t1 : 2 : t2: 2: References: AtomicInteger (Java SE
17 & JDK 17) - Oracle
NEW QUESTION # 29
Given the code fragment:
What is the result?
- A. 010 optional (Newyear)
- B. False true true optional (Newyear)
- C. True true false NewYear
- D. 0110
Answer: B
Explanation:
The code fragment is using the stream methods allMatch, anyMatch, noneMatch, and findFirst on a list of strings called specialDays. These methods are used to perform matching operations on the elements of a stream, such as checking if all, any, or none of the elements satisfy a given predicate, or finding the first element that matches a predicate1. The predicate in this case is that the string equals "Labour" or "Halloween". The output will be:
False: because not all of the elements in specialDays are equal to "Labour" or "Halloween".
true: because at least one of the elements in specialDays is equal to "Labour" or "Halloween".
true: because none of the elements in specialDays are equal to both "Labour" and "Halloween".
Optional[NewYear]: because the first element in specialDays that matches the predicate is "NewYear", and the findFirst method returns an Optional object that may or may not contain a non-null value2.
NEW QUESTION # 30
Given:
and the code fragment:
- A. 300.00
CellPhone,ToyCar,Motor,Fan - B. 100.00 CellPhone,ToyCar
- C. 100.00
CellPhone,ToyCar,Motor,Fan - D. 300.00 CellPhone.ToyCar
Answer: A
Explanation:
Explanation
The code fragment is using the Stream API to perform a reduction operation on a list of ElectricProduct objects. The reduction operation consists of three parts: an identity value, an accumulator function, and a combiner function. The identity value is the initial value of the result, which is 0.0 in this case. The accumulator function is a BiFunction that takes two arguments: the current result and the current element of the stream, and returns a new result. In this case, the accumulator function is (a,b) -> a + b.getPrice (), which means that it adds the price of each element to the current result. The combiner function is a BinaryOperator that takes two partial results and combines them into one. In this case, the combiner function is (a,b) -> a + b, which means that it adds the two partial results together.
The code fragment then applies a filter operation on the stream, which returns a new stream that contains only the elements that match the given predicate. The predicate is p -> p.getPrice () > 10, which means that it selects only the elements that have a price greater than 10. The code fragment then applies a map operation on the filtered stream, which returns a new stream that contains the results of applying the given function to each element. The function is p -> p.getName (), which means that it returns the name of each element.
The code fragment then calls the collect method on the mapped stream, which performs a mutable reduction operation on the elements of the stream using a Collector. The Collector is Collectors.joining (","), which means that it concatenates the elements of the stream into a single String, separated by commas.
The code fragment then prints out the result of the reduction operation and the result of the collect operation, separated by a new line. The result of the reduction operation is 300.00, which is the sum of the prices of all ElectricProduct objects that have a price greater than 10. The result of the collect operation is CellPhone,ToyCar,Motor,Fan, which is the concatenation of the names of all ElectricProduct objects that have a price greater than 10.
Therefore, the output of the code fragment is:
300.00 CellPhone,ToyCar,Motor,Fan
References: Stream (Java SE 17 & JDK 17) - Oracle, Collectors (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 31
Given:
What is the result?
- A. A RuntimeException is thrown
- B. Wtablechair tableChair
- C. Tablechair Tablechair
- D. wTableChair TableChair
- E. Compilation fails
Answer: E
Explanation:
The code fragment will fail to compile because the class name and the constructor name do not match. The class name is Furniture, but the constructor name is Wtable. This will cause a syntax error. The correct way to define a constructor is to use the same name as the class name. Therefore, the code fragment should change the constructor name to Furniture or change the class name to Wtable.
NEW QUESTION # 32
Given the product class:
And the shop class:
What is the result?
- A. Cookie 0.0 0.0
- B. Cookie 3.99 2.99
- C. An exception is produced at runtime
- D. Cookie 0.0 2.99
- E. Cookie 2.99 2.99
- F. Compilation fails
Answer: F
Explanation:
Explanation
The code fragment will fail to compile because the readObject method in the Product class is missing the
@Override annotation. The readObject method is a special method that is used to customize the deserialization process of an object. It must be declared as private, have no return type, and take a single parameter of type ObjectInputStream. It must also be annotated with @Override to indicate that it overrides the default behavior of the ObjectInputStream class. Without the @Override annotation, the compiler will treat the readObject method as a normal method and not as a deserialization hook. Therefore, the code fragment will produce a compilation error. References: Object Serialization - Oracle, [ObjectInputStream (Java SE 17 & JDK 17) - Oracle]
NEW QUESTION # 33
Which statement is true about modules?
- A. Automatic and unnamed modules are on the module path.
- B. Only automatic modules are on the module path.
- C. Automatic and named modules are on the module path.
- D. Only unnamed modules are on the module path.
- E. Only named modules are on the module path.
Answer: C
Explanation:
A module path is a sequence of directories that contain modules or JAR files. A named module is a module that has a name and a module descriptor (module-info.class) that declares its dependencies and exports. An automatic module is a module that does not have a module descriptor, but is derived from the name and contents of a JAR file. Both named and automatic modules can be placed on the module path, and they can be resolved by the Java runtime. An unnamed module is a special module that contains all the classes that are not in any other module, such as those on the class path. An unnamed module is not on the module path, but it can read all other modules.
NEW QUESTION # 34
Given:
Which statement is true?
- A. The program throws ClassCastException
- B. The program fails to compile.
- C. The program throws StockException.
- D. The program throws outofStockException.
Answer: B
Explanation:
Explanation
The answer is B because the code fragment contains a syntax error that prevents it from compiling. The code fragment tries to catch a StockException in line 10, but the catch block does not have a parameter of type StockException. The catch block should have a parameter of type StockException, such as:
catch (StockException e) { // handle the exception }
This is required by the Java syntax for the catch clause, which must have a parameter that is a subclass of Throwable. Without a parameter, the catch block is invalid and causes a compilation error.
Option A is incorrect because the program does not throw a StockException, as it does not compile.
Option C is incorrect because the program does not throw an OutofStockException, as it does not compile.
Option D is incorrect because the program does not throw a ClassCastException, as it does not compile.
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
The try-with-resources Statement (The Java™ Tutorials > Essential Classes > Exceptions) The catch Blocks (The Java™ Tutorials > Essential Classes > Exceptions)
NEW QUESTION # 35
Which statement is true?
- A. After the timed wait expires, the waited thread moves to the terminated state.
- B. A thread in waiting state must handle InterrupedException.
- C. thread in waiting state consumes CPU cycles.
- D. IllegalStateException is thrown if a thread in waiting state is moved back to runnable.
Answer: B
Explanation:
Explanation
A thread in waiting state is waiting for another thread to perform a particular action, such as calling notify() or notifyAll() on a shared object, or terminating a joined thread. A thread in waiting state can be interrupted by another thread, which will cause the waiting thread to throw an InterruptedException and return to the runnable state. Therefore, a thread in waiting state must handle InterruptedException, either by catching it or declaring it in the throws clause. References: Thread.State (Java SE 17 & JDK 17), [Thread (Java SE 17 & JDK 17)]
NEW QUESTION # 36
Given the code fragment:
Which two statements at Line nl independently enable you to print 1250?
- A. Integer res = 250 + s:
- B. Integer res = 250 + integer . valueof (s);
- C. Integer res = 250 + integer (s2):
- D. Integer res= 250 + s2;
- E. Integer res = 250 + integer.parseint (s)
- F. Integer res = 250;
Answer: B,E
Explanation:
Res = + s2;
Explanation:
The code fragment is creating a string variable "s" with the value "10_00" and an integer variable "s2" with the value 10. The string "s" is using an underscore as a separator for readability, which is allowed in Java SE 171. The question is asking for two statements that can add 250 to the numeric value of "s" and assign it to an integer variable "res". The correct answers are A and E because they use the methods parseInt and valueOf of the Integer class to convert the string "s" to an integer. Both methods interpret the string as a signed decimal integer and return the equivalent int or Integer value23. The other options are incorrect because they either use invalid syntax, such as B and C, or they do not convert the string "s" to an integer, such as D and F. Reference: Binary Literals (The Java™ Tutorials > Learning the Java Language > Numbers and Strings), Integer (Java SE 17 & JDK 17), Integer (Java SE 17 & JDK 17)
NEW QUESTION # 37
Given:
What is the result?
- A. 0
- B. A runtime exception is thrown.
- C. Nothing is printed because of an indefinite loop.
- D. 1
- E. 2
- F. 3
- G. 4
- H. Compilation fails.
Answer: H
Explanation:
The code will not compile because the variable 'x' is declared as final and then it is being modified in the switch statement. This is not allowed in Java. A final variable is a variable whose value cannot be changed once it is initialized1. The switch statement tries to assign different values to 'x' depending on the value of 'y', which violates the final modifier. The compiler will report an error: The final local variable x cannot be assigned. It must be blank and not using a compound assignment. Reference: The final Keyword (The Java™ Tutorials > Learning the Java Language > Classes and Objects)
NEW QUESTION # 38
......
Verified 1z1-829 Exam Dumps Q&As - Provide 1z1-829 with Correct Answers: https://www.validtorrent.com/1z1-829-valid-exam-torrent.html
Pass Your 1z1-829 Dumps Free Latest Oracle Practice Tests: https://drive.google.com/open?id=1dtledBgx937GdCFdD6n0AxZo_aP8w1nQ