Oracle 1Z0-047 dumps - in .pdf

1Z0-047 pdf
  • Exam Code: 1Z0-047
  • Exam Name: Oracle Database SQL Expert
  • Updated: Oct 14, 2026
  • Q & A: 264 Questions and Answers
  • PDF Price: $59.99
  • Free Demo

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  • Exam Code: 1Z0-047
  • Exam Name: Oracle Database SQL Expert
  • Updated: Oct 14, 2026
  • Q & A: 264 Questions and Answers
  • PDF Version + PC Test Engine + Online Test Engine
  • Value Pack Total: $119.98  $79.99
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Oracle 1Z0-047 dumps - Testing Engine

1Z0-047 Testing Engine
  • Exam Code: 1Z0-047
  • Exam Name: Oracle Database SQL Expert
  • Updated: Oct 14, 2026
  • Q & A: 264 Questions and Answers
  • Software Price: $59.99
  • Testing Engine

About Oracle 1Z0-047 Exam braindumps

In 2026, some candidates chase 1Z0-047 for career growth, others for personal ability. The motive matters less than the method, and ValidTorrent keeps the method simple: 264 verified practice questions, updated as the exam evolves.

Oracle 1Z0-047 Exam Overview:

Certification Vendor:Oracle
Exam Name:Oracle Database SQL Expert
Exam Number:1Z0-047
Exam Duration:120 minutes
Exam Format:Multiple Response, Multiple Choice
Related Certifications:Oracle Database SQL Fundamentals I (1Z0-051)
Real Exam Qty:70
Certificate Validity Period:Typically 3 years (depends on Oracle policy)
Exam Price:Approximately USD 195 (varies by region)
Passing Score:Not publicly disclosed (Oracle doesn’t publish exact pass marks)
Available Languages:Spanish, English, Japanese, German
Sample Questions:Free Download 1Z0-047 pdf braindumps
Exam Way:Onsite at Pearson VUE or online proctored delivery
Pre Condition:No formal prerequisite, but SQL Fundamentals knowledge recommended
Official Syllabus URL:https://www.oracle.com/education/certification/

Oracle 1Z0-047 Exam Syllabus Topics:

SectionObjectives
Controlling User Access- System and object privileges
- Granting roles and privileges
Reporting Aggregated Data- Group functions and GROUP BY
- HAVING clause usage
Regular Expression Support- Using regular expressions in SQL
Creating and Managing Schema Objects- Views, sequences, and indexes
- Private and public synonyms
Using DDL Statements- Understand data types and constraints
- Create and manage tables
Hierarchical Retrieval- CONNECT BY and tree-structured queries
Using Single-Row Functions- Conversion functions
- Character, number, and date functions
Using Set Operators- UNION, INTERSECT, MINUS
- Control order of result sets
Managing Data in Different Time Zones- Datetime functions and timezone handling
Restricting and Sorting Data- Sort query results
- Limit rows returned
Managing Objects with Data Dictionary Views- Use data dictionary views
Generating Reports by Grouping Related Data- ROLLUP and CUBE operations
- GROUPING SETS
Manipulating Large Data Sets- Flashback query usage
- Multitable INSERTs and MERGE
Displaying Data from Multiple Tables- Joins (inner, outer, self)
- Cartesian products
Retrieving Data Using the SQL SELECT Statement- List capabilities of SQL SELECT
- Execute basic SELECT statements
- Understand schema object behavior
Manipulating Data- Transaction control
- INSERT, UPDATE, DELETE
Using Subqueries- Define and use various subquery types
- Correlated subqueries and WITH clause

Before You Start: Oracle Database SQL Expert Answers

1Z0-047 is passed with Not publicly disclosed (Oracle doesn’t publish exact pass marks), and the official exam fee is Approximately USD 195 (varies by region). Fixing these numbers early helps you set a measurable practice target.

The 1Z0-047 exam contains 70 questions to complete in 120 minutes minutes. Rehearsing under the same limit on the ValidTorrent engine turns pacing into a trained habit.

Choose the version of Oracle Database SQL Expert you want, one, two, or all three, add it to the cart, and complete payment through the secure Credit Card checkout. The download link then arrives by email within about a minute, so your study starts without wasted time.

The package includes 264 practice questions for the 1Z0-047 exam. The count is set through analysis of a large volume of data, so the set matches the scope of the real test without padding.

  • Using Subqueries ()
  • Displaying Data from Multiple Tables ()
  • Reporting Aggregated Data ()

Divide your time according to each topic's weight.

Payment runs through the Credit Card system, a globally used online payment network. We never share your personal information with third parties without your permission, and we never send spam, so your details stay where they belong.

No formal prerequisite, but SQL Fundamentals knowledge recommended

Oracle Database SQL Expert Sample Questions:

Question #1

View the Exhibit and examine the structure of the EMPLOYEES table.
Evaluate the following SQL statement: SELECT employee_id, last_name, job_id, manager_id FROM employees START WITH employee_id = 101 CONNECT BY PRIOR employee_id=manager_id;
Which statement is true regarding the output for this command?

  • A. It would return a hierarchical output starting with the employee whose EMPLOYEE_ID is101, followed by employees up to one level below him or her in the hierarchy.
  • B. It would return a hierarchical output starting with the employee whose EMPLOYEE_ID is 101, followed by employees below him or her in the hierarchy.
  • C. It would return a hierarchical output starting with the employee whose EMPLOYEE_ID is 101, followed by the employee to whom he or she reports.
  • D. It would return a hierarchical output starting with the employee whose EMPLOYEE_ID is 101, followed by his or her peers.
Reveal Solution  Discussion  0

Correct Answer: B  🗳️

Question #2

The ORDERS table belongs to the user OE. OE has granted the SELECT privilege on the ORDERS table to the user HR. Which statement would create a synonym ORD so that HR can execute the following query successfully? SELECT'FROM ord;

  • A. CREATE PUBLIC SYNONYM ord FOR oe.orders; This command is issued by the database administrator.
  • B. CREATE SYNONYM ord FOR oe.orders; This command is issued by the database administrator.
  • C. CREATE PUBLIC SYNONYM ord FOR orders; This command is issued by OE.
  • D. CREATE SYNONYM ord FOR orders; This command is issued by OE.
Reveal Solution  Discussion  0

Correct Answer: A  🗳️

Question #3

View the Exhibit and examine the description of the ORDERS table.
Evaluate the following SQL statement:
SELECT order_id, customer_id FROM orders WHERE order_date > 'June 30 2001';
Which statement is true regarding the execution of this SQL statement?

  • A. It would not execute because 'June 30 2001' in the WHERE condition is not enclosed within double quotation marks.
  • B. It would not execute because 'June 30 2001' in the WHERE condition cannot be converted implicitly and needs the use of the TO_DATE conversion function for proper execution.
  • C. It would not execute because 'June 30 2001' in the WHERE condition cannot be converted implicitly and needs the use of the TO_CHAR conversion function for proper execution.
  • D. It would execute and would return ORDER_ID and CUSTOMER_ID for all records having ORDER_DATE greater than 'June 30 2001'.
Reveal Solution  Discussion  0

Correct Answer: B  🗳️

Question #4

Which CREATE TABLE statement is valid?

  • A. CREATE TABLE ord_details
    (ord_no NUMBER(2),
    item_no NUMBER(3),
    ord_date date DEFAULT SYSDATE NOT NULL,
    CONSTRAINT ord_pk PRIMARY KEY (ord_no, item_no));
  • B. CREATE TABLE ord_details
    (ord_no NUMBER(2) UNIQUE, NOT NULL,
    item_no NUMBER(3),
    ord_date date DEFAULT SYSDATE NOT NULL);
  • C. CREATE TABLE ord_details
    (ord_no NUMBER(2) ,
    item_no NUMBER(3),
    ord_date date DEFAULT NOT NULL,
    CONSTRAINT ord_uq UNIQUE (ord_no),
    CONSTRAINT ord_pk PRIMARY KEY (ord_no));
  • D. CREATE TABLE ord_details
    (ord_no NUMBER(2) PRIMARY KEY,
    item_no NUMBER(3) PRIMARY KEY,
    ord_date date NOT NULL);
Reveal Solution  Discussion  0

Correct Answer: A  🗳️

Question #5

View the Exhibit and examine the structure of the ORDER_ITEMS table.
You need to display the ORDER_ID of the order that has the highest total value among all the
orders in the ORDER_ITEMS table.
Which query would produce the desired output?

  • A. SELECT order_id
    FROM order_items
    WHERE (unit_price*quantity) = (SELECT MAX(unit_price*quantity) FROM order_items
    GROUP BY order_id);
  • B. SELECT order_id
    FROM order_items
    WHERE(unit_price*quantity) = (SELECT MAX(unit_price*quantity) FROM order_items)
    GROUP BY order_id;
  • C. SELECT order_id
    FROM order_items
    WHERE(unit_price*quantity) = MAX(unit_price*quantity)
    GROUP BY order_id;
  • D. SELECT order_id
    FROM order_items
    GROUP BY order_id
    HAVING SUM(unit_price*quantity) =(SELECT MAX(SUM(unit_price*quantity))
    FROM order_items GROUP BY order_id);
Reveal Solution  Discussion  0

Correct Answer: D  🗳️

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